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Last updated: October 22, 2026 · Written by the Math Made Easy math teachers

Standards: 6.EE.A.1, 6.EE.A.2c · Level: Grade 6
Problem 2 Evaluating powers
34 = 3 × 3 × 3 × 3 = 81. 72 = 49. 26 = 64. 103 = 1,000. 81, 49, 64, 1,000.
Problem 3 Writing with exponents
Count the factors. (a) 93 (b) 55 (c) 1.52.
Problem 4 Square floor
There are 7 rows of 7 tiles.
72 = 49 tiles.
Problem 5 Powers of 10
The exponent counts the zeros. 102 = 100, 104 = 10,000, 106 = 1,000,000.
Problem 6 Powers of 10 from numbers
100,000 has 5 zeros and 10,000,000 has 7 zeros. 105 and 107.
Problem 7 Left to right
Subtraction and addition share a level, so go left to right: 18 − 6 = 12, then 12 + 4 = 16.
Problem 8 Multiplication first
5 + 3 × 7 = 5 + 21 = 26. (5 + 3) × 7 = 8 × 7 = 56. 26 and 56; the parentheses force the addition to happen first.
Problem 9 Division and exponent
(a) Left to right: 40 ÷ 5 = 8, then 8 × 2 = 16. (b) Exponent first: 23 = 8, then 9 + 8 = 17. (a) 16 (b) 17.
Problem 10 Power and subtraction
Powers: 52 = 25 and 23 = 8. Multiply: 6 × 3 = 18. Then 25 + 18 − 8 = 35.
Problem 11 Grouping and exponent
Grouping: 10 − 4 = 6. Exponent: 62 = 36. Left to right: 6 × 36 = 216, and 216 ÷ 9 = 24.
Problem 12 Find the error
The student added first: 8 + 2 = 10, then 10 × 5 = 50. Multiplication must come first: 2 × 5 = 10, then 8 + 10 = 18.
Problem 13 Parentheses with a power
Grouping: 2 + 3 = 5. Exponent: 52 = 25. Multiply: 3 × 25 = 75. Subtract: 100 − 75 = 25.
Problem 14 Crate of blocks
Each layer has 3 × 3 = 9 blocks and there are 3 layers: 9 × 3 = 27. 33 = 27 blocks.
Problem 15 Spreading news
Day 1: 31, day 2: 32 = 9, and each day multiplies by 3. Day 5 is 35 = 3 × 3 × 3 × 3 × 3 = 243 people.
Problem 16 Growing culture
Doubling 6 times multiplies by 26 = 64. Expression: 5 × 26 = 5 × 64 = 320 cells.
Problem 17 Stadium seats
Ten times as many adds one factor of 10: 106. 105 = 100,000 and 106 = 1,000,000. Stadium 105 = 100,000; arena 106 = 1,000,000.
Problem 18 Food truck bill
Total before coupon: 8 × 3 + 5 × 2 = 24 + 10 = 34. Expression: (8 × 3 + 5 × 2 − 4) ÷ 2 = (24 + 10 − 4) ÷ 2 = 30 ÷ 2. Each friend pays $15.
Problem 19 Two-part expressions
(a) 32 − 1 = 8; 82 = 64; 64 ÷ 8 = 8; 4 + 8 = 12. (b) (3 + 4) × 5 − 2 = 7 × 5 − 2 = 35 − 2 = 33. (a) 12 (b) (3 + 4) × 5 − 2.
Problem 20 Tiles with a rug
The room has 92 = 81 tiles and the rug covers 42 = 16.
81 − 16 = 65 tiles, from the expression 92 − 42.
