← Back to the Volume Of Cylinders Cones Spheres worksheet
Last updated: October 22, 2026 · Written by the Math Made Easy math teachers
Standards: 8.G.C.9 · Level: Grade 8
Problem 2 Diameter given
The radius is 12 ÷ 2 = 6 in.
V = π · 6² · 5 = π · 36 · 5.
180π in³
Problem 3 First cone
V = (1/3)π · 3² · 7 = (1/3)π · 63.
21π in³
Problem 4 Wider cone
V = (1/3)π · 6² · 9 = (1/3)π · 324.
108π cm³
Problem 5 First sphere
V = (4/3)π · 3³ = (4/3)π · 27.
36π ft³
Problem 6 Cylinder with 3.14
V = 3.14 · 5² · 8 = 3.14 · 200.
628 cm³
Problem 7 Big sphere
The radius is 9 cm. V = (4/3)π · 9³ = (4/3)π · 729 = 4π · 243.
972π cm³
Problem 8 Cone with 3.14
V = (1/3) · 3.14 · 5² · 12 = 3.14 · 100.
314 in³
Problem 9 Sphere with 3.14
V = (4/3) · 3.14 · 6³ = (4/3) · 3.14 · 216 = 288 · 3.14.
904.32 in³
Problem 10 Find the height of a cylinder
225π = π · 5² · h = 25πh.
h = 225 ÷ 25.
9 cm
Problem 11 Find the height of a cone
96π = (1/3)π · 6² · h = 12πh.
h = 96 ÷ 12.
8 cm
Problem 12 Cone versus cylinder
The cone holds one third of the cylinder, so the cylinder holds 3 times as much.
3 · 40π = 120π.
120π in³
Problem 13 Find the radius
(4/3)πr³ = (32/3)π, so 4r³ = 32 and r³ = 8.
r = ∛8 = 2.
2 in.
Problem 14 Hemisphere bowl
V = (1/2)(4/3)π · 5³ = (2/3)π · 125 = (250/3)π.
(250/3)π ≈ 261.8.
(250/3)π in³ ≈ 261.8 in³
Problem 15 Water tank
The radius is 4 ft. V = 3.14 · 4² · 10 = 3.14 · 160.
3.14 · 160 = 502.4.
The tank holds 502.4 ft³.
Problem 16 Ice cream cone
Cone: (1/3)π · 3² · 10 = 30π. Hemisphere: (2/3)π · 3³ = 18π.
Total: 30π + 18π = 48π. With 3.14: 48 · 3.14 = 150.72.
48π cm³ ≈ 150.72 cm³
Problem 17 Grain silo
Cylinder: π · 6² · 20 = 720π. Hemisphere: (2/3)π · 6³ = 144π.
Total: 864π. With 3.14: 864 · 3.14 = 2,712.96.
864π ft³ ≈ 2,712.96 ft³
Problem 18 Ball in a tube
Tube: π · 3² · 6 = 54π. Ball: (4/3)π · 27 = 36π.
Empty space: 54π − 36π = 18π, and 18 · 3.14 = 56.52.
18π in³ ≈ 56.52 in³
Problem 19 Sand pile
The radius is 6 ft. V = (1/3) · 3.14 · 6² · 5 = 3.14 · 60 = 188.4 ft³.
188.4 ÷ 40 = 4.71, so 5 loads are needed, since the last load is partly full.
188.4 ft³; 5 loads
Problem 20 Pouring water
Cone volume: (1/3)π · 6² · 9 = 108π cm³.
Cylinder: π · 4² · h = 16πh = 108π, so h = 108 ÷ 16 = 6.75.
6.75 cm