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Last updated: October 22, 2026 · Written by the Math Made Easy math teachers

Standards: AP Statistics Unit 3 (2026-27) · Level: Grade 12 AP Statistics
Question 1 Confidence Interval (3 points)
(a) Random sample; 400 is less than 10% of a large county; 158 and 242 are at least 10. (b) p̂ = 0.395, SE = 0.02444, ME = 0.0479, interval (0.347, 0.443). (c) We are 95% confident that the true proportion of county voters who plan to vote for the bond is between 0.347 and 0.443.
(0.347, 0.443)
Scoring: 1 point conditions, 1 point interval, 1 point interpretation in context.
Question 2 Sample Size (2 points)
n ≥ (1.645/0.04)2(0.5)(0.5) = 422.82. Round up.
n = 423
Scoring: 1 point for the formula with p̂ = 0.5, 1 point for rounding up correctly.
Question 3 Interval Justification (2 points)
Program X: the interval (0.08, 0.20) does not contain 0 and is all positive, so there is convincing evidence that X improves the graduation rate. Program Y: the interval (−0.03, 0.11) contains 0, so a difference of 0 is plausible and there is not convincing evidence of a difference.
X: yes; Y: no
Scoring: 1 point each program, with the reason about 0.
Question 4 Significance Test (3 points)
(a) H0: p = 0.50; Ha: p ≠ 0.50. Random sample, 150 is under 10% of the plays, and 150(0.5) = 75 for both counts. (b) p̂ = 0.4067, SE = √(0.25/150) = 0.0408, z = −2.286. The two-sided p-value is 2 × 0.0111 = 0.0222. (c) Since 0.0222 < 0.05, we reject H0; there is convincing evidence that the true win proportion differs from 0.50 (it appears to be lower).
z ≈ −2.29, p-value ≈ 0.022; reject H0
Scoring: 1 point each part: hypotheses and conditions, statistic and p-value, conclusion in context.
Question 5 p-Value and Decision (2 points)
(a) If the true proportion of students who work part-time were 0.30, the probability of getting a sample proportion as large as the one observed, or larger, would be 0.021. (b) Since 0.021 < 0.05, reject H0: there is convincing evidence that the true proportion is greater than 0.30.
Reject H0
Scoring: 1 point for a correct interpretation, 1 point for the decision with context.
Question 6 Errors in Context (2 points)
Type I: deciding that the defect rate is above 2% when it is actually 2% (rejecting a true H0), which could stop production unnecessarily. Type II: not finding convincing evidence that the rate is above 2% when it is really higher, so defective items continue to be shipped.
Type I: reject true H0; Type II: fail to reject false H0
Scoring: 1 point for each error described in context.
Question 7 Difference of Two Proportions (3 points)
(a) Random and independent samples; counts 52, 78, 36 and 84 are all at least 10. (b) p̂A = 0.400, p̂B = 0.300, difference 0.100. SE = 0.0600, ME = 0.1175. Interval (−0.018, 0.218). (c) The interval contains 0, so there is not convincing evidence of a difference.
(−0.018, 0.218); no convincing evidence
Scoring: 1 point each part.
Question 8 Power (3 points)
(a) Power is the probability of rejecting H0 when a particular alternative value of the parameter is true (1 − β). (b) Increase the sample size, or use a larger α, or test an alternative that is farther from the null value. (c) A larger α raises the probability of a Type I error.
Power = P(reject H0 | Ha true)
Scoring: 1 point each part.
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