Skip to content
Home › AP Calculus AB Math › AP Calculus AB Tests › Differential Equations Test Answer Key with Scoring – AP Calculus AB

Differential Equations Test Answer Key with Scoring – AP Calculus AB

← Back to the Differential Equations test

Last updated: October 22, 2026 · Written by the Math Made Easy math teachers

AP Calculus AB Math Test Answer Keys – Mathbot, the Math Made Easy robot coach, with free printable test answer keys for AP Calculus AB

Worked solutions and scoring guides follow. Award separation and integration points independently, and require the constant of integration. Answers without an initial-condition step cannot earn full credit on particular-solution questions.

Standards: AP Calculus AB Unit 7 · Level: Grade 12 AP Calculus AB

Question 1 Solution with an initial condition (2 points)

Write dydx = 3(y − 2). Separation gives y − 2 = Ae3x. With y(0) = 7, A = 5. Answer (A).

Scoring: 2 points for the correct choice; 1 point for a correct separated form.

Question 2 Matching a slope field (2 points)

The segments are horizontal along y = x, so the slope involves x − y. At (0, 2) the segment slopes steeply downward: x − y = −2. This rules out (C), whose slope there would be +2. Answer (B).

Scoring: 2 points for the correct choice; 1 point for checking a point.

Question 3 Separable equation (3 points)

(a) Separate: y dy = 6x2 dx. Integrate: y2/2 = 2x3 + C.

(b) At (1, 3): 9/2 = 2 + C, so C = 5/2. Then y2 = 4x3 + 5. Since y(1) > 0, y = √(4x3 + 5).

Scoring: Part (a): 1 point for separating, 1 point for integrating both sides with a constant. Part (b): 1 point.

Question 4 Radioactive decay (3 points)

(a) m(t) = 250e−0.04t.

(b) Solve e−0.04t = 1/2: t = ln 2/0.04 ≈ 17.3 years.

(c) Solve 40 = 250e−0.04t: t = ln(6.25)/0.04 ≈ 45.8 years.

Scoring: 1 point per part.

Question 5 Verifying a solution (3 points)

(a) y′ = 2e2x + 1. Then y′ − 2y = 2e2x + 1 − 2e2x − 2x = 1 − 2x. The equation holds.

(b) y(0) = e0 + 0 = 1.

Scoring: Part (a): 1 point for the derivative, 1 point for the substitution. Part (b): 1 point.

Question 6 Slope field reasoning (3 points)

(a) The slope is zero for y = 0 and y = 4.

(b) The solution starts at 1 with positive slope and cannot cross the equilibrium y = 4, so the limit is 4.

(c) d2ydx2 = (4 − 2y)dydx. For 0 < y < 2, both factors are positive, so the solution is concave up.

−112345−112345xy
The solution through (0, 1).

Scoring: 1 point per part.

Question 7 Cooling model (2 points)

(a) Solving gives T = 20 + 60e−0.1t. So T(5) = 20 + 60e−0.5 ≈ 56.4°F.

(b) As t → ∞, e−0.1t → 0, so T approaches 20°F.

Scoring: 1 point per part.

Question 8 Tangent line approximation (2 points)

(a) The slope is x2 − y = 1 − 2 = −1 at (1, 2). The tangent line is y = 2 − (x − 1).

(b) At x = 1.1: 2 − 0.1 = 1.9.

Scoring: 1 point per part.

Mis à jour le