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Graphing Parabolas and Key Features: Algebra 1 Math Lesson

Last updated: October 22, 2026 · Written by the Math Made Easy math teachers

Algebra 1 Math Lessons – Mathbot, the Math Made Easy robot coach, with free printable lessons for Algebra 1

Looking for algebra 1 quadratic functions? Then this Algebra 1 lesson on Graphing Parabolas and Key Features explains each idea step by step, with worked examples.

Quick answer: A quadratic function graphs as a parabola. Its vertex is the lowest point when the leading coefficient is positive and the highest point when it is negative. The mirror line is x = −b2a. Standard form reveals the y-intercept, vertex form reveals the vertex, and factored form reveals the zeros.

Standards: F-IF.C.7a, F-IF.C.8a, F-IF.B.4, A-SSE.B.3b · Level: Grade 9 Algebra 1

What does the graph of a quadratic function look like?

When a ≠ 0, the rule f(x) = ax² + bx + c is quadratic. Its picture is a parabola, the U-shaped path of a basketball shot, or the area of a rectangle as one side stretches.

Key features

  • Vertex: the turning point, a minimum when a > 0 and a maximum when a < 0.
  • Axis of symmetry: a mirror line, x = h, that cuts the parabola into two matching halves.
  • Intercepts: the points where the curve meets the x-axis or the y-axis.
-4-3-2-11234-5-4-3-2-112345678xya < 0a > 0
a > 0 opens up (minimum); a < 0 opens down (maximum).

Which three forms should you know?

  • Standard form y = ax² + bx + c gives the point (0, c) at once, and the mirror line x = −b2a.
  • Vertex form y = a(x − h)² + k shows the turning point (h, k).
  • Factored form y = a(x − p)(x − q) shows crossings of the x-axis at p and q.
0123456-6-4-2246xyvertex (3, 4)(1, 0)(5, 0)
y = −(x − 3)² + 4: the vertex (h, k) = (3, 4).

How do you find the vertex from standard form?

Method

  1. Compute x = −b ÷ (2a), the x-coordinate of the turning point.
  2. Put that x back into the rule to get y.
  3. Plot (x, y), then add the intercepts to sketch the curve.
Worked example

y = x² − 4x − 5. Here x = 4 ÷ 2 = 2 and y = 4 − 8 − 5 = −9, so the turning point is (2, −9). Factoring gives (x − 5)(x + 1), so the curve crosses the x-axis at 5 and −1 and the y-axis at −5.

-2-1123456-10-8-6-4-2246xy(−1, 0)(5, 0)(0, −5)vertex (2, −9)axis x = 2
Key features of y = x² − 4x − 5.

How does completing the square give the vertex form?

Add and subtract the square of half the x-coefficient. For y = x² + 6x + 5, half of 6 is 3, so y = (x² + 6x + 9) − 9 + 5 = (x + 3)² − 4. The vertex is (−3, −4).

Common mistake

In (x + 3)² the vertex has x = −3, not 3. The sign inside the parentheses is the opposite of h.

Mathbot’s tip

The vertex sits halfway between the two zeros, so average the zeros to get the axis.

Key points to remember

  • The parabola opens up if a > 0 and down if a < 0.
  • Axis of symmetry in standard form: x = −b2a.
  • Vertex form y = a(x − h)² + k has vertex (h, k).
  • Factored form y = a(x − p)(x − q) has zeros p and q.
  • Completing the square turns standard form into vertex form.

Graphing Parabolas and Key Features: frequently asked questions

How do you find the vertex of a parabola?

In standard form, compute x = −b2a, then substitute it into the function to get y. In vertex form y = a(x − h)² + k, the vertex is simply (h, k).

What is the axis of symmetry?

It is the vertical line through the vertex that splits the parabola into two mirror-image halves. Its equation is x = h, where h is the x-coordinate of the vertex.

How do you know whether a parabola has a maximum or a minimum?

Look at the sign of a. If a is positive the graph opens up and the vertex is a minimum. If a is negative it opens down and the vertex is a maximum.

What does completing the square do?

It rewrites x² + bx + c as (x + b2)² + k, a perfect square plus a constant. This reveals the vertex and makes some equations easy to solve.

How can you find the zeros of a quadratic function?

Set the function equal to 0 and factor, if possible. In factored form y = a(x − p)(x − q) the zeros p and q can be read directly from the factors.

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