← Back to the Complex Numbers Polar Form test
Last updated: October 22, 2026 · Written by the Math Made Easy math teachers

Standards: N-CN.B.4, N-CN.B.5, N-CN.B.6, N-CN.A.3 · Level: Grade 12 Precalculus
Question 1 Reading the Plane (2 points)
The point is 5 units left and 3 units up, so z = −5 + 3i.
(a) |z| = √(25 + 9) = √34.
(b) z̄ = −5 − 3i.
Answer: √34; −5 − 3i
Scoring: 1 point for each part.
Question 2 Rectangular to Polar (2 points)
(a) r = √(8 + 8) = 4.
(b) The reference angle is 45° and the number is in Quadrant II, so θ = 135°, and the polar form is 4(cos 135° + i sin 135°).
Answer: r = 4; 4(cos 135° + i sin 135°)
Scoring: 1 point for each part.
Question 3 Polar to Rectangular (2 points)
cos 210° = −√32 and sin 210° = −12. So a = 10·(−√32) = −5√3 and b = 10·(−12) = −5.
Answer: −5√3 − 5i
Scoring: 1 point for the two values from the unit circle, 1 point for the result.
Question 4 Product and Quotient (2 points)
(a) 6 · 3 = 18 and 100° + 40° = 140°, so 18(cos 140° + i sin 140°).
(b) 6 ÷ 3 = 2 and 100° − 40° = 60°, so 2(cos 60° + i sin 60°).
Answer: (a) 18(cos 140° + i sin 140°); (b) 2(cos 60° + i sin 60°)
Scoring: 1 point for each part.
Question 5 Distance and Midpoint (2 points)
Difference: 5 − 8i. Distance = √(25 + 64) = √89 ≈ 9.43.
Midpoint = 1 + 6i2 = 12 + 3i.
Answer: √89 and 12 + 3i
Scoring: 1 point for the distance, 1 point for the midpoint.
Question 6 Using De Moivre (3 points)
(a) 35 = 243 and 5 · 12° = 60°, so 243(cos 60° + i sin 60°).
(b) √3 − i = 2(cos(−30°) + i sin(−30°)). The seventh power is 27(cos(−210°) + i sin(−210°)) = 128(cos 150° + i sin 150°) = 128(−√32 + 12i) = −64√3 + 64i.
Answer: (a) 243(cos 60° + i sin 60°); (b) −64√3 + 64i
Scoring: (a) 1 point. (b) 1 point for the polar form of √3 − i and 1 point for the correct power and final rectangular form.
Question 7 Cube Roots of −8 (3 points)
−8 = 8(cos 180° + i sin 180°). The cube roots have modulus 2 and angles (180° + 360°k)/3 = 60°, 180°, 300°.
2(cos 60° + i sin 60°) = 1 + √3i; 2(cos 180° + i sin 180°) = −2; 2(cos 300° + i sin 300°) = 1 − √3i.
Answer: 1 + √3i, −2, 1 − √3i
Scoring: 1 point for the modulus and angles, 2 points for the three correct roots (1 point if only two).
Question 8 Scaling and Turning (2 points)
(a) 3i(5 + 2i) = 15i + 6i2 = −6 + 15i.
(b) |P| = √29 and |Q| = √(36 + 225) = √261 = 3√29. Q is three times as far from the origin as P, and it is P turned 90° counterclockwise.
Answer: Q = −6 + 15i; |Q| = 3|P|
Scoring: 1 point for each part.
Question 9 Modulus of a Product (2 points)
zw = 3 − 12i + i − 4i2 = 7 − 11i.
|zw| = √(49 + 121) = √170. Also |z| = √10 and |w| = √17, and √10 · √17 = √170.
Answer: zw = 7 − 11i and both sides equal √170
Scoring: 1 point for the product, 1 point for the comparison of moduli.
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